      ## Print this Job Post # Decimal to binary conversion

C program to convert decimal to binary: c language code to convert an integer from decimal number system(base-10) to binary number system(base-2). Size of integer is assumed to be 32 bits. We use bitwise operators to perform the desired task. We right shift the original number by 31, 30, 29, ..., 1, 0 bits using a loop and bitwise AND the number obtained with 1(one), if the result is 1 then that bit is 1 otherwise it is 0(zero).

## C programming code

#include <stdio.h>
#include<conio.h>
void main()
{
int n, c, k;
printf("Enter an integer in decimal number system\n");
scanf("%d", &n);
printf("%d in binary number system is:\n", n);
for (c = 31; c >= 0; c--)
{
k = n >> c;
if (k & 1)
printf("1");
else
printf("0");
}
printf("\n");
getch();
}

Above code only prints binary of integer, but we may wish to perform operations on binary so in the code below we are storing the binary in a string. We create a function which returns a pointer to string which is the binary of the number passed as argument to the function.

## C code to store decimal to binary conversion in a string

#include <stdio.h>
#include <stdlib.h>
#include<conio.h>
char *decimal_to_binary(int);
void main()
{
int n, c, k;
char *pointer;
printf("Enter an integer in decimal number system\n");
scanf("%d",&n);
pointer = decimal_to_binary(n);
printf("Binary string of %d is: %s\n", n, t);
free(pointer);
getch();
}
char *decimal_to_binary(int n)
{
int c, d, count;
char *pointer;
count = 0;
pointer = (char*)malloc(32+1);
if ( pointer == NULL )
exit(EXIT_FAILURE);
for ( c = 31 ; c >= 0 ; c-- )
{
d = n >> c;
if ( d & 1 )
*(pointer+count) = 1 + '0';
else
*(pointer+count) = 0 + '0';
count++;
}
*(pointer+count) = '\0';
return  pointer;
}