C program to find frequency of characters in a string

This program computes frequency of characters in a string i.e. which character is present how many times in a string. For example in the string "code" each of the character 'c', 'o', 'd', and 'e' has occurred one time. Only lower case alphabets are considered, other characters (uppercase and special characters) are ignored. You can easily modify this program to handle uppercase and special symbols.

C programming code

#include <stdio.h>

#include <string.h>

#include<conio.h> 

void main()

{

   char string[100];

   int c = 0, count[26] = {0};

   printf("Enter a string\n");

   gets(string);

   while ( string[c] != '\0' )

   {

      /* Considering characters from 'a' to 'z' only */

    if ( string[c] >= 'a' && string[c] <= 'z' ) 

    count[string[c]-'a']++;

    c++;

   }

    for ( c = 0 ; c < 26 ; c++ )

   {

     if( count[c] != 0 )

     printf("%c occurs %d times in the entered string.\n",c+'a',count[c]);

   }

   getch();

}

Explanation of "count[string[c]-'a']++", suppose input string begins with 'a' so c is 0 initially and string[0] = 'a' and string[0]-'a' = 0 and we increment count[0] i.e. a has occurred one time and repeat this till complete string is scanned.

Output of program: