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Thursday, May 22, 2014

C program to reverse an array

This program reverses the array elements. For example if a is an array of integers with three elements such that
a[0] = 1
a[1] = 2
a[2] = 3
Then on reversing the array will be
a[0] = 3
a[1] = 2
a[0] = 1

Given below is the c code to reverse an array.

C programming code

#include <stdio.h>
#include<conio.h> 
void main()
{
   int n, c, d, a[100], b[100];
   clrscr();
   printf("Enter the number of elements in array\n");
   scanf("%d", &n);
   printf("Enter the array elements\n");
   for (c = 0; c < n ; c++)
   scanf("%d", &a[c]);
   for (c = n - 1, d = 0; c >= 0; c--, d++)
   b[d] = a[c];
   for (c = 0; c < n; c++)
   a[c] = b[c];
   printf("Reverse array is\n");
   for (c = 0; c < n; c++)
   printf("%d\n", a[c]);
   getch();
}

Output of program:


Reverse array by swapping (without using additional memory)

#include <stdio.h>
#include<conio.h> 
void main() 
{
  int array[100], n, c, temp, end;
  clrscr(); 
  scanf("%d", &n);
  end = n - 1;
  for (c = 0; c < n; c++) 
 {
  scanf("%d", &array[c]);
  }
  for (c = 0; c < n/2; c++) 
 {
  temp = array[c];
  array[c]   = array[end];
  array[end] = temp;
  end--;
  }
  printf("Reversed array elements are:\n");
  for (c = 0; c < n; c++) {
  printf("%d\n", array[c]);
  }
  getch();
}


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